গতি- ওয়ানশট ক্লাস - পদার্থবিজ্ঞান।। এসএসসি ২০২৫! | ACS Future School

Summary

Join ACS Future School for an exciting one-shot class on "Gati" or motion in Physics, curated specially for the SSC 2025 aspirants. This captivating class dives deep into the core concepts of motion, measurements, and related equations. The discussion covers various speed equations, acceleration principles, and vector illustrations in a fun, intuitive way. From understanding basic velocity and displacement fundamentals to complex acceleration problems, this session is a thorough walkthrough of essential physics topics that will strengthen the students' conceptual understanding. With numerous practical examples and problem-solving techniques, this class aims to build a solid foundation in physics for students gearing up for their SSC exams.

Highlights

• Engaging introduction to motion and mechanics for SSC students! 🎓
• Step-by-step walkthrough of motion equations and problems. 🧩
• Simplified explanations of velocity and acceleration concepts. 🏃‍♂️
• Interactive examples to solidify understanding of Physics. 🖼️
• Fascinating insights into real-world applications of physics principles. 🌍

Key Takeaways

• Master the basic concepts of motion effortlessly! 🚀
• Unlock the mysteries of velocity and acceleration. 💨
• Tackle complex physics problems with ease. 🧠
• Fun, engaging learning with examples galore! 🎓
• Build a solid foundation for SSC 2025 Physics. 📚

Overview

In this dynamic one-shot class by ACS Future School, gently navigate the essentials of motion in physics – a topic every SSC aspirant must master. The session begins with an introduction to basic mechanics and gradually advances into more complex physics problems tailored for the SSC 2025 syllabus.

The instructor breaks down intricate concepts like velocity, acceleration, and vector physics, making them comprehensible and enjoyable. Fun examples sprinkled throughout the class keep students intrigued and help solidify their understanding of these pivotal topics.

With a focus on engaging storytelling and practical problem-solving, students are walked through equations and given tricks to approach physics exams with confidence. This session is not just educational but also a fascinating insight into the real-world applications of physics, enhancing the learning experience.

Chapters

• 00:00 - 01:00: Introduction and Opening Remarks This chapter serves as an introduction and features the speaker's opening remarks. The speaker greets the audience with a simple 'hello everyone,' setting the stage for what is likely to follow in the subsequent chapters.
• 01:00 - 02:00: Concept of Mechanics This chapter explores the fundamental concepts of mechanics, which is the branch of physics concerned with the behavior of physical bodies when subjected to forces or displacements.
• 02:00 - 03:00: Motion Equations and Problems The chapter "Motion Equations and Problems" likely covers fundamental motion equations used in mechanics, such as Newton's laws of motion. It may involve discussing topics relevant to mechanical engineering, including understanding motion in physical systems, solving related mathematical problems, and applying these concepts to practical engineering scenarios. The transcript mentioning 'mechanic engineering department' suggests a link to applied engineering contexts, possibly illustrating the real-world application of theoretical principles discussed in this chapter.
• 03:00 - 04:00: Graphical Analysis of Motion The chapter delves into the graphical representation of motion, exploring various ways to depict the movement of objects through graphs. It covers concepts such as distance-time and velocity-time graphs, explaining how they can be used to analyze and interpret motion. Key focus is given to understanding slopes and areas under the graphs, which correspond to speed, distance, and acceleration. The graphical analysis helps students visualize and comprehend motion in a more intuitive manner.
• 04:00 - 05:00: Advanced Problem Solving on Motion This chapter delves into advanced problem-solving techniques specifically within the context of motion. It begins with a review of basic concepts such as displacement, velocity, and acceleration, then transitions into more complex scenarios involving relative motion and non-linear equations. The chapter demonstrates how to approach and solve problems involving multiple objects in motion, providing illustrative examples and detailed solutions. Key strategies such as breaking down problems into smaller parts, using diagrams, and identifying known versus unknown variables are emphasized. Moreover, the chapter incorporates calculus-based methods for solving motion problems, offering insights into the application of derivatives and integrals in predicting future motion states. Practical applications and real-world examples are used throughout to contextualize these advanced methods in everyday settings like car chases, sports, and machinery. Throughout, the chapter stresses the importance of logical reasoning and critical thinking, encouraging students to question assumptions and verify their solutions. It ends with a set of challenging problems designed to test the students' advanced knowledge and problem-solving skills in motion dynamics.
• 05:00 - 06:00: Discussion on Velocity and Acceleration The chapter titled 'Discussion on Velocity and Acceleration' provides an insight into the physics concepts of velocity and acceleration. It likely explores the definitions of velocity and acceleration, explains how they relate to each other, and discusses their significance in understanding motion. The chapter may include mathematical formulas for calculating velocity and acceleration, examples illustrating these concepts, and possible real-world applications to enhance comprehension. It may also cover the differences between speed and velocity and give scenarios where acceleration is positive, negative, or zero.
• 06:00 - 07:00: Equation Derivations and Examples This chapter likely covers the detailed derivations of various equations and provides practical examples to aid in understanding. However, the transcript provided is incomplete, reducing clarity on the specific equations discussed.
• 07:00 - 08:00: Conceptual Problems and their Solutions The chapter titled 'Conceptual Problems and their Solutions' discusses various types of conceptual problems that can arise in different fields. It provides several examples of such problems and delves into methods and strategies for solving them effectively. The chapter emphasizes the importance of understanding the underlying concepts before attempting to solve the problems. It also highlights common pitfalls and misunderstandings that can occur when dealing with conceptual issues and suggests techniques to avoid them. Additionally, the chapter may include real-world case studies or hypothetical scenarios to illustrate the problem-solving process in action.
• 08:00 - 09:00: Understanding Projectile Motion This chapter, titled 'Understanding Projectile Motion,' delves into the core principles of projectile motion, emphasizing the mathematical foundation using quadratic expressions. The transcript provided references 'simple x²,' suggesting a focus on parabolic trajectories common in projectile motion analyses. While the transcript is brief, it likely forms the basis for explaining how objects move under the influence of gravity, following a curved path characteristic of quadratic equations in physics. The chapter possibly covers initial velocity, angle of launch, maximum height, and range, all integral components of understanding projectile dynamics.
• 09:00 - 10:00: Multiple Motion Scenarios This chapter explores multiple motion scenarios, likely within a physics context, as suggested by the presence of mathematical expressions. It may involve equations of motion, represented by the expression 'x² + x + 1', which could relate to positions or velocities as functions of time. The chapter might be discussing scenarios in which these expressions model real-world situations, particularly those involving man-made or natural objects in motion. The text suggests a focus on the application of these mathematical concepts in explaining physical phenomena.
• 10:00 - 11:00: Recap and Important Formulas The chapter initially provides a recap of key concepts discussed in previous sections, ensuring that foundational knowledge is solid before introducing any new material. It emphasizes understanding the underlying principles that have been covered so far.
• 11:00 - 12:00: Applications and Practical Examples The chapter titled 'Applications and Practical Examples' illustrates various real-world scenarios where theoretical concepts are implemented. It emphasizes the importance of applying knowledge to solve practical problems and provides numerous examples across different fields to demonstrate this application. The chapter may cover case studies, success stories, and detailed instances of how theoretical ideas have been transformed into practical solutions, facilitating a deeper understanding of their utility and impact in everyday contexts.
• 12:00 - 13:00: Q&A and Final Thoughts The chapter provides a comprehensive exploration of vectors, focusing on their mathematical properties and applications in various fields.

গতি- ওয়ানশট ক্লাস - পদার্থবিজ্ঞান।। এসএসসি ২০২৫! | ACS Future School Transcription

• 00:00 - 00:30 hello everyone
• 00:30 - 01:00 at [Music]
• 01:00 - 01:30 mechanic engineering department
• 01:30 - 02:00 what is simply rashanti
• 02:00 - 02:30 for
• 02:30 - 03:00 for foran
• 03:00 - 03:30 speciically
• 03:30 - 04:00 just
• 04:00 - 04:30 simple x²
• 04:30 - 05:00 + x + 1 x 2 2 s+ 2 man x² + x + 1 Man physic
• 05:00 - 05:30 two
• 05:30 - 06:00 for for
• 06:00 - 06:30 Vector
• 06:30 - 07:00 man man
• 07:00 - 07:30 for a CH
• 07:30 - 08:00 K 1 kilom 1 kilometer fine
• 08:00 - 08:30 hello
• 08:30 - 09:00 fore for for
• 09:00 - 09:30 for
• 09:30 - 10:00 for vect vect vce
• 10:00 - 10:30 V for
• 10:30 - 11:00 SC
• 11:00 - 11:30 pro toit pro a
• 11:30 - 12:00 specied i r
• 12:00 - 12:30 1 whatever it is 1 high
• 12:30 - 13:00 voltage high voltage low voltage flow
• 13:00 - 13:30 same
• 13:30 - 14:00 that's why
• 14:00 - 14:30 fine okay
• 14:30 - 15:00 [Music] for
• 15:00 - 15:30 but okay fine a
• 15:30 - 16:00 for either one or two or
• 16:00 - 16:30 just simply for
• 16:30 - 17:00 number
• 17:00 - 17:30 but number
• 17:30 - 18:00 four do M A do m b a m b a m b
• 18:00 - 18:30 UT
• 18:30 - 19:00 simp displacement displacment
• 19:00 - 19:30 sorry distance fore foree
• 19:30 - 20:00 so this will be the minimum distance D
• 20:00 - 20:30 [Music] minimum okay fine
• 20:30 - 21:00 right point B chally
• 21:00 - 21:30 a for
• 21:30 - 22:00 fin for
• 22:00 - 22:30 L Square o a square
• 22:30 - 23:00 oine root over o a 10 10 Square 15
• 23:00 - 23:30 square root over 10
• 23:30 - 24:00 square J 15 Square answer
• 24:00 - 24:30 [Music] 180 to 7 8 m
• 24:30 - 25:00 okay simply 18 0278 18278
• 25:00 - 25:30 for okay fine okay next problem
• 25:30 - 26:00 a a
• 26:00 - 26:30 for for
• 26:30 - 27:00 1 by4 of 1x 4 2 pi into r r I into r value 3 by 2 3x 2 3 2 3 by 2
• 27:00 - 27:30 pi answer 4 71 24 m for
• 27:30 - 28:00 [Music]
• 28:00 - 28:30 root over 3² + 3 squ root 18 4 24 26
• 28:30 - 29:00 for just minus okay for
• 29:00 - 29:30 [Music]
• 29:30 - 30:00 T1 D1
• 30:00 - 30:30 S1 S2 sor
• 30:30 - 31:00 simply divid equation so a situation
• 31:00 - 31:30 D1 s
• 31:30 - 32:00 [Music] for
• 32:00 - 32:30 same
• 32:30 - 33:00 for so
• 33:00 - 33:30 so okay for
• 33:30 - 34:00 V1 V1 10 by
• 34:00 - 34:30 5 2 [Music] m by t s met second
• 34:30 - 35:00 thir L inverse 1 10 by
• 35:00 - 35:30 V2 2 second3 14 by 2
• 35:30 - 36:00 2
• 36:00 - 36:30 man man a
• 36:30 - 37:00 for 2 m 2
• 37:00 - 37:30 so simply sh no doy
• 37:30 - 38:00 s1y t1y s22 s33 v s by S by S VT s VT
• 38:00 - 38:30 only for uniform velocity uniform velocity vity simple
• 38:30 - 39:00 10 15 V1 T1 10 into s
• 39:00 - 39:30 s S2 simply v22 S2 Val 15 into 8 15 into 8 90 M total s total s S1 + S2 this is equal simp M total s S1 plus S2 x x
• 39:30 - 40:00 okay fine
• 40:00 - 40:30 next okay
• 40:30 - 41:00 for S1 a a a V2 S2 B
• 41:00 - 41:30 s V3 V1 not equals to V2 not equals to V3 for
• 41:30 - 42:00 for
• 42:00 - 42:30 for V1 V2 V3
• 42:30 - 43:00 for this is equal simply Mo Shon by m sh M Shon by m okay
• 43:00 - 43:30 fine S1 S2 S3 S1 S2 S3 V1 V2 v33
• 43:30 - 44:00 equ S1 S1 plus S2 Plus S3 T1 S1 by V1 t2y S2 by vs2 3y S3 by V3
• 44:00 - 44:30 this is the equation of gar by average velocity V [Applause] bar v23
• 44:30 - 45:00 10 m second v 15 M second V2 man R 20 m/ second V3 S1
• 45:00 - 45:30 second s by V 1 second s by V 2 second s by V 1
• 45:30 - 46:00 30
• 46:00 - 46:30 45 85 met 45 20 45 20 2.25 ch
• 46:30 - 47:00 2.25 2.25 2 1 5.25 5.25 8 5.25 V average total distance
• 47:00 - 47:30 total distance total v 78.75 m
• 47:30 - 48:00 S1 S2 S3 T1 T2 T3 perfectly
• 48:00 - 48:30 [Music] okay okay sit
• 48:30 - 49:00 [Music] okay fine
• 49:00 - 49:30 S1 by S2 divided by T1 by T2 S1 man or S2 2 S1 T1 S1 by V1 T2 S2 by V2 2 by 1 by V1 1 by
• 49:30 - 50:00 V2 but
• 50:00 - 50:30 G
• 50:30 - 51:00 for okay for
• 51:00 - 51:30 C
• 51:30 - 52:00 1x4 of 2 pi
• 52:00 - 52:30 r already 1 by 4 into 2
• 52:30 - 53:00 pi by 5 [Music] this is the average speed aage
• 53:00 - 53:30 veloc simply root s s Square rooot 200 root over 200 so
• 53:30 - 54:00 byun 200 ID 60 second okay
• 54:00 - 54:30 okay b c
• 54:30 - 55:00 40 s s by s s by 2 according to the
• 55:00 - 55:30 equation V average velocity this is equal total distance but total displacement T T1 plus
• 55:30 - 56:00 T2 s by 21 s by 2 30 4 time2 S by S by
• 56:00 - 56:30 402 s by 8 T1 Val s by 60 T2 value by 80 s s T1 s by 60 T2
• 56:30 - 57:00 s s 1 by 60 + 1 by 80 s s 1 iD 1X 60 1 by 60 + 1 by 80 Man 1 / 7 by
• 57:00 - 57:30 240 one answer 34 285 7 m/s a directly
• 57:30 - 58:00 complely process
• 58:00 - 58:30 very fine
• 58:30 - 59:00 most probably answer 12.7
• 59:00 - 59:30 okay fine object a point O point a point h point
• 59:30 - 60:00 B
• 60:00 - 60:30 fely
• 60:30 - 61:00 fine VY v t
• 61:00 - 61:30 [Music] for V is greater than uy vector
• 61:30 - 62:00 U is greater than V Del V
• 62:00 - 62:30 simply Delta V by T that means
• 62:30 - 63:00 V minus divid t this will be equal acceleration sit
• 63:00 - 63:30 very important part very much important partel equ vus uid t netive
• 63:30 - 64:00 s -2 m/s Square
• 64:00 - 64:30 s negative acceleration deer
• 64:30 - 65:00 [Music] Square LT inverse 2 bracket unit me/ second squarey LT inverse 2
• 65:00 - 65:30 okay for
• 65:30 - 66:00 [Music] spor bar
• 66:00 - 66:30 spor barar a
• 66:30 - 67:00 V2 V1 V1 o V2 V1 o V2
• 67:00 - 67:30 man that's [Music] completely to [Music]
• 67:30 - 68:00 V1 big V2 big same V1 V2 V1 is not equal V2
• 68:00 - 68:30 very much important concept and very much important question for exam
• 68:30 - 69:00 vus U by t z acceleration Z for
• 69:00 - 69:30 10 10
• 69:30 - 70:00 millisecond 10 Mond okay
• 70:00 - 70:30 2 me second okay
• 70:30 - 71:00 sh B but final velocity minus initial velocity vus
• 71:00 - 71:30 H -2 minus U value U value 2 me second posi -2 - 2 -4 m/
• 71:30 - 72:00 second Delta V by T Delta V value4 time value 10 MC 10 10 into 10
• 72:00 - 72:30 ^3 400 newon oh newon meter per second meter per second Square Accel
• 72:30 - 73:00 ACC
• 73:00 - 73:30 40 squ perfect
• 73:30 - 74:00 answer [Music] okay that is only applicable for
• 74:00 - 74:30 s u Plus at Square
• 74:30 - 75:00 v² u s+ 2 U u v s a
• 75:00 - 75:30 t number V number oh you sorry t a meaning
• 75:30 - 76:00 Sol
• 76:00 - 76:30 okay related problem 5 m Square
• 76:30 - 77:00 396 kilm hour 396 second 3 990 6 kilom
• 77:00 - 77:30 hour throughout the M met 396
• 77:30 - 78:00 K 96 into kilom per houry kilometer per hour kilometer
• 78:00 - 78:30 Hour 1 hour 60 into 60
• 78:30 - 79:00 second 396 into M secondly kilom hour 3.6
• 79:00 - 79:30 3.6 okay ini
• 79:30 - 80:00 v a
• 80:00 - 80:30 V u+ A V value U value z a value 5 into T So T Val by 22 m per second oh sorry t
• 80:30 - 81:00 simp 8 me 23 me
• 81:00 - 81:30 for sorry
• 81:30 - 82:00 fine 8 m second 23 m
• 82:00 - 82:30 S1 U1 t plus half of A1 T1 Square s U1 T sorry U2 T2 U2
• 82:30 - 83:00 T2 J half of A2 T2 s S1 Val s ut+ half of
• 83:00 - 83:30 a² acceleration ID
• 83:30 - 84:00 4 2 0 into T half of 2 into sare 2 4 16 m s 16 similar
• 84:00 - 84:30 s s 8 BC 3 8 into 3 half of B final velocity 23 minus initial
• 84:30 - 85:00 velocity 8id M square into a 5 S 8 into .5 into 5 into 3 squ 3
• 85:00 - 85:30 Square 46 5 m total s S1 + S2 a 46.5 16 62.5 62.5
• 85:30 - 86:00 62.5 half a into 7
• 86:00 - 86:30 s 62.5 49 by 2 into a 62.5 into 2 49 2 2551 m per second Square
• 86:30 - 87:00 50 m
• 87:00 - 87:30 [Music]
• 87:30 - 88:00 UT plus half of a squ s Val U value 30 t plus half of a value
• 88:00 - 88:30 to v² u² + 2 a s a form 2 into
• 88:30 - 89:00 a 30 into t² 5 2 2.5 t² + 30t minus
• 89:00 - 89:30 x 2.5 30 minus X act value 4 second
• 89:30 - 90:00 16 okay hello problem
• 90:00 - 90:30 me
• 90:30 - 91:00 s UT + half of a
• 91:00 - 91:30 sare s one U Zer half a t value one square 2 acceleration so a actually 2 m/s
• 91:30 - 92:00 square acceleration 2 m/ second Square
• 92:00 - 92:30 AC
• 92:30 - 93:00 t u plus half of a squ s value a a m meter 2 m u value a z half 2 me
• 93:00 - 93:30 second T 2 so tun2 1.41 a 1.41
• 93:30 - 94:00 second T AB plus TBC 1.41 1 second BC 0.41 second that's it simple problem 12
• 94:00 - 94:30 72 throughout
• 94:30 - 95:00 the
• 95:00 - 95:30 for B Point C point a
• 95:30 - 96:00 by U1 plus half of A1 4u half of a square 4+ 8
• 96:00 - 96:30 a x this is our equation number one
• 96:30 - 97:00 s a u t of AC Plus of a d of a
• 97:00 - 97:30 s s AC BC U
• 97:30 - 98:00 into half of a sare this is our equation number two
• 98:00 - 98:30 un
• 98:30 - 99:00 fine secondine
• 99:00 - 99:30 V
• 99:30 - 100:00 03 second V simply s by T
• 100:00 - 100:30 413 into 4 1.2 M 0 1 one m/ second second s of
• 100:30 - 101:00 BC 0.11 into 4 0.44 m a
• 101:00 - 101:30 complely
• 101:30 - 102:00 add
• 102:00 - 102:30 so 0.5
• 102:30 - 103:00 same same color okay
• 103:00 - 103:30 easy ma easy this will be initial velocity 90 km 3.60 3.6 25 V 0 me 6
• 103:30 - 104:00 second 60 simp vus u v value z u value 25 time value 0.41
• 104:00 - 104:30 67 0.41 67 m/ squ UT plus half of a t² s value
• 104:30 - 105:00 s 2541 67 into time Val 60 square that will be our
• 105:00 - 105:30 answer okay oh dou
• 105:30 - 106:00 okay second 3.6 side meter per second just 3 3.6
• 106:00 - 106:30 15 m/ second
• 106:30 - 107:00 this is the value of acceleration
• 107:00 - 107:30 AOC
• 107:30 - 108:00 15 M second
• 108:00 - 108:30 Square V sare +
• 108:30 - 109:00 2 2 into 15 into 100 2 into 15 into 100 root over answer I have 54 77 23 m/
• 109:00 - 109:30 Second this is less this is our answer for
• 109:30 - 110:00 okay fine
• 110:00 - 110:30 [Music]
• 110:30 - 111:00 15 s u sare + 2 a 60 squ 0 mistake 0 S 2 into a into
• 111:00 - 111:30 s 60 S 2 15 M this is the answer
• 111:30 - 112:00 okay fine 5
• 112:00 - 112:30 G number one 10
• 112:30 - 113:00 10er 2 m Square [Music] 5 me second 5 m per
• 113:00 - 113:30 second acceleration acceleration 3 m/ second Square flag
• 113:30 - 114:00 FL number one step number one
• 114:00 - 114:30 for same same s u
• 114:30 - 115:00 a plus half of a t² Val is U value U value 10 T value Tel 2 half into 2 into
• 115:00 - 115:30 t² Val 10 t + t² this is our s this is our equation number one second car first car second s Val s fine U value
• 115:30 - 116:00 five 5 t plus half of 3 3 into t² number equation
• 116:00 - 116:30 10 t + t² a right side 5T + 1.5
• 116:30 - 117:00 t² 10 plus 10 + T 5 + 1.5t so 10 second T Val 10
• 117:00 - 117:30 second ex
• 117:30 - 118:00 for okay topet
• 118:00 - 118:30 sare problem V uare 2 s
• 118:30 - 119:00 v s 2 [Music]
• 119:00 - 119:30 bullet same concept same for
• 119:30 - 120:00 second
• 120:00 - 120:30 v u a s formula v
• 120:30 - 121:00 s u + 2 s sorry [Music]
• 121:00 - 121:30 problem
• 121:30 - 122:00 for 9 cm 9 cm
• 122:00 - 122:30 0 m second situation
• 122:30 - 123:00 [Music] for u 2 A U by two U by 2 square u
• 123:00 - 123:30 u acceleration key same same color same
• 123:30 - 124:00 by 100 u s by 4 U sare plus by 100 into a 1 by 4us 1 3 by 4
• 124:00 - 124:30 u² 18 by 100 into a a300 divid 72
• 124:30 - 125:00 [Music] U same equation v² u² + 2 a S U by 2 square plus 2
• 125:00 - 125:30 into same 300 by 72 U S U by
• 125:30 - 126:00 4us plusus a22 300 by 36 u² into s 300 by 36 u² into s u² by
• 126:00 - 126:30 4 4 answer 36 4 into answer3 meter that actually 3 cm so this is our answer
• 126:30 - 127:00 only for McQ shortcut is only for McQ
• 127:00 - 127:30 for McQ for McQ
• 127:30 - 128:00 D Air B Air B U by n u ke
• 128:00 - 128:30 x d / n² minus one a d d nus one 9
• 128:30 - 129:00 cm 9 cm x d value 9 2 s minus 1 Man 9 4 minus 3 Man 3 3 cm
• 129:00 - 129:30 short okay 23
• 129:30 - 130:00 23 2 by3 of U
• 130:00 - 130:30 3 by2 n Val 3 by 2 1.5
• 130:30 - 131:00 okay 40 5 cm 30 cm
• 131:00 - 131:30 400 me sorry 30 cmet
• 131:30 - 132:00 u² + 2 a
• 132:00 - 132:30 s Sameer same Force same acceleration
• 132:30 - 133:00 sorry S V Val v u sare plus 2 a next problem
• 133:00 - 133:30 3D
• 133:30 - 134:00 same apprach
• 134:00 - 134:30 u² + 2
• 134:30 - 135:00 s z u² + 2 into a into s Val Aus u s
• 135:00 - 135:30 6 U + 2 2 into a into s
• 135:30 - 136:00 0 2 u² oh sorry 4 u² plus 2 into acceleration u² by 6D acceleration C Z 4 u² + 4 u²
• 136:00 - 136:30 minus 2 u² by 3D into S U u² by 3D into s U Square uu sare simp s
• 136:30 - 137:00 12al this is the answer this is approach one approach two
• 137:00 - 137:30 appr minus 2 a s u squ minus 2 a s
• 137:30 - 138:00 fine s is proportional to u s very important
• 138:00 - 138:30 part same S1 by U1 sorry S1 by S2 U1 is Square by U2 Square S1 by
• 138:30 - 139:00 s2u by U2 U1 u u U2 twice U whole Square S1 by S2 1 by 4 S2 4 S1 very much important line
• 139:00 - 139:30 S2 4 S1 answer
• 139:30 - 140:00 s 12 for
• 140:00 - 140:30 short
• 140:30 - 141:00 shortcut
• 141:00 - 141:30 shortcut Toka any Square Square
• 141:30 - 142:00 sare this is shortcut
• 142:00 - 142:30 sare this is short fory any Square two square okay
• 142:30 - 143:00 okay 6.5m
• 143:00 - 143:30 2 6
• 143:30 - 144:00 it second second it third
• 144:00 - 144:30 second a
• 144:30 - 145:00 [Music] situation throughout the PA acceleration constant S2 minus
• 145:00 - 145:30 X S1 S2 S1 sorry 2 2
• 145:30 - 146:00 S3 S2 S3 tus s of t t s of tus
• 146:00 - 146:30 tus of T minus s of T minus one formula formula U + half a into 2T - 1 U + half a a into 2T minus
• 146:30 - 147:00 1 through the Val three second second Val two
• 147:00 - 147:30 s f Val formula U plus half a 2T minus one U Val Z half 5 m/ Square 2 into 5 5us 1
• 147:30 - 148:00 simply into 5 into met this is the answer this is the answer
• 148:00 - 148:30 s formula U + half a 2 T minus 1 2 into tus
• 148:30 - 149:00 1 2 tus 1 2 tus equation U + 9 by 2 a P this is our equation number one U + 9 by 2 a this is equal p equation number
• 149:00 - 149:30 one u+ a 2us 1 u+ half of 2T do into pus one half into U + U + 19 by 2 a this is equal
• 149:30 - 150:00 100 number one 9 2 p 1 2 5 acceleration
• 150:00 - 150:30 10 square s u plus half of a squ t value for
• 150:30 - 151:00 done okay priv car 21
• 151:00 - 151:30 me track acceleration track acceleration 2 m/s square 2 m per second
• 151:30 - 152:00 Square 20 U + a 2 tus 1 0 + half a value 2 into 2 into 2 20us one answer simple
• 152:00 - 152:30 problem very important problem very much important problem private CH private priv priv 21 me me truck 21 m per
• 152:30 - 153:00 second 21 m per second 22 m/s
• 153:00 - 153:30 Square for
• 153:30 - 154:00 simply S Plus
• 154:00 - 154:30 8 s
• 154:30 - 155:00 s + 8 this is equal s VT VT s+ 8 V value 21 into T this is our equation
• 155:00 - 155:30 number one equation number one s
• 155:30 - 156:00 s tracker t plus half of tracker acceleration a into t² s simply t s 21
• 156:00 - 156:30 S 80 21 t t us 21 T 80
• 156:30 - 157:00 z 80 5 [Music] Second
• 157:00 - 157:30 for for truck
• 157:30 - 158:00 TR
• 158:00 - 158:30 for 5 Second
• 158:30 - 159:00 for
• 159:00 - 159:30 16 same problem
• 159:30 - 160:00 that's it
• 160:00 - 160:30 forall sudro sudro sudro ji b b onlyto
• 160:30 - 161:00 acceleration only
• 161:00 - 161:30 G for
• 161:30 - 162:00 okays
• 162:00 - 162:30 for important relation a relation V is proportional to
• 162:30 - 163:00 T okay
• 163:00 - 163:30 exive for
• 163:30 - 164:00 U plus GT U Val V simply GT
• 164:00 - 164:30 V is proportional to T V isal
• 164:30 - 165:00 GT H GT number v² 2 g h Val h s u u z plus half of a square Val
• 165:00 - 165:30 G half GT sare V sare U sare plus 2 a s u Val Z 2 a s Val for
• 165:30 - 166:00 velocity v u minus GT minus minus
• 166:00 - 166:30 equation U minus GT H equation U minus half of GT s OPP
• 166:30 - 167:00 fin 2 [Music] G oh sorry u s minus 2 G
• 167:00 - 167:30 veloc okay H half GT
• 167:30 - 168:00 sare H half G UT + half of a s zero
• 168:00 - 168:30 [Music] the same half GT Square so half G value 9.8 r t sare Val 10 square into 9.8 2 into 9.8 2
• 168:30 - 169:00 me S by 49 but again
• 169:00 - 169:30 very much conceptual problem problem [Music] Char
• 169:30 - 170:00 meter me
• 170:00 - 170:30 2 g h a value V1 root over 2 into G value 9.8 r H Val H 4 M root over 2 into 9.8 into 4
• 170:30 - 171:00 8. 85 44 for
• 171:00 - 171:30 firste second second v² U sare minus 2 g h V Val Z V2 s minus 2 into 9.8 3
• 171:30 - 172:00 m vot 2 into 9.8 into 3 76681 m/ second V1 V2 0 1 0.01
• 172:00 - 172:30 second final velocity minus initial velocity divided by time final velocity final velocity V2 initial velocity minus V1 /
• 172:30 - 173:00 T 66681 minus 88544 divided by 01
• 173:00 - 173:30 V v2i
• 173:30 - 174:00 V1 negative
• 174:00 - 174:30 okay 19.6 meter Eon CH meter
• 174:30 - 175:00 sorry for6 equation H half G
• 175:00 - 175:30 t² 19.2 19.6 into 2 9.8 root answer 2 m 2 second. H half GT s same equation 19.6
• 175:30 - 176:00 minus 1 18.6 half G T1 s so T1 18.6 into 2 pug 9.8 root Answer 1 Point 94 83 second
• 176:00 - 176:30 2 T1 h
• 176:30 - 177:00 uus
• 177:00 - 177:30 gtus GT final velocity Z uus g into
• 177:30 - 178:00 T1 so answer 2 into 9.2 by 9.8 so that will be the answer
• 178:00 - 178:30 Max 2 uh met go
• 178:30 - 179:00 for foron
• 179:00 - 179:30 [Music]
• 179:30 - 180:00 T1 41.1
• 180:00 - 180:30 m h g t² h value 4 4.1 half into 9.1
• 180:30 - 181:00 9.81 s so T1 T1 Val 44.1 into 2 98 Ro answer 3
• 181:00 - 181:30 for 44.1 340 man 0.12 97 at second T1 value t
• 181:30 - 182:00 okay
• 182:00 - 182:30 [Music] 20
• 182:30 - 183:00 [Music]
• 183:00 - 183:30 H Max formly u s by 2G formula
• 183:30 - 184:00 H Max minus 5 velocity equation key V half into sorry V just g into
• 184:00 - 184:30 t g into h g Val 9.8 h H maxus 5 maxus 5 formula V 2 g h g h h maxus
• 184:30 - 185:00 5 easily h g t² h h maxus
• 185:00 - 185:30 5 u g
• 185:30 - 186:00 homework
• 186:00 - 186:30 [Music] second for
• 186:30 - 187:00 B
• 187:00 - 187:30 Dy B Dy t t fori x
• 187:30 - 188:00 x Milito h u minus half GT
• 188:00 - 188:30 squ number equation 600 H half GT s
• 188:30 - 189:00 hus X half GT minus UT a minus or a minus plus half GT s half GT sare GT GT
• 189:00 - 189:30 sare so T 600 ID u u for
• 189:30 - 190:00 90
• 190:00 - 190:30 km 90 km
• 190:30 - 191:00 completely different issue 90 km hour 90 by 3.6 3.6 90 3.6 25 m/
• 191:00 - 191:30 second 25 M second this is
• 191:30 - 192:00 Max H Max u² / 2G vity inial v
• 192:00 - 192:30 g u² minus 2 g h v u² minus 2 g h Val maximum H H Max so H Max equation that is equal u² by 2G
• 192:30 - 193:00 sit
• 193:00 - 193:30 foron C
• 193:30 - 194:00 Boron C t t u by
• 194:00 - 194:30 G EAS U minus GT velocity uus
• 194:30 - 195:00 GT so 2 into U value 25 divided by 9 9.8 2 into 25 9.8 5.1 second 5.1 second
• 195:00 - 195:30 51 51
• 195:30 - 196:00 so
• 196:00 - 196:30 concep problem concep
• 196:30 - 197:00 problem and most important but
• 197:00 - 197:30 22 m
• 197:30 - 198:00 first drop Z second second 2D
• 198:00 - 198:30 2 2 2 for
• 198:30 - 199:00 for first drop second drop third drop fourth drop analysis
• 199:00 - 199:30 for Dy pH Dy pH m ban
• 199:30 - 200:00 T third fourth that
• 200:00 - 200:30 means phot as B
• 200:30 - 201:00 third Dr Dr [Music]
• 201:00 - 201:30 D3 itoo phal
• 201:30 - 202:00 H1 first
• 202:00 - 202:30 drop first drop H1 half of g into T1 Square 22 22 22 into 2 9.8 root Answer
• 202:30 - 203:00 2. 1 1 89 second 2189 second T1 by 3
• 203:00 - 203:30 T1 T1 by 3763 second H2 half of
• 203:30 - 204:00 GT2 Square answer into two square into .5 into 99.8 9.77 78 M
• 204:00 - 204:30 .77 simp H3 H3 half of G T3 S35 into 9.8 P3 value 7063 squ
• 204:30 - 205:00 2. 44 44 m for
• 205:00 - 205:30 ad
• 205:30 - 206:00 okay
• 206:00 - 206:30 for for
• 206:30 - 207:00 origi
• 207:00 - 207:30 sit
• 207:30 - 208:00 POS
• 208:00 - 208:30 G by
• 208:30 - 209:00 9.8 m/ second Square very much important
• 209:00 - 209:30 part negative fine for [Music]
• 209:30 - 210:00 s UT plus
• 210:00 - 210:30 half U value u t u value positive a positive DC a value key a value negative minus half G
• 210:30 - 211:00 t² by G Val Val
• 211:00 - 211:30 G G
• 211:30 - 212:00 0 m per second fine G
• 212:00 - 212:30 h
• 212:30 - 213:00 plus half at Square half at Square s Val
• 213:00 - 213:30 hus g into t² H half G t²
• 213:30 - 214:00 sare okay
• 214:00 - 214:30 zus g into t v minus GT ah velocity minus
• 214:30 - 215:00 forus for
• 215:00 - 215:30 okay 100
• 215:30 - 216:00 10 me
• 216:00 - 216:30 second
• 216:30 - 217:00 for simple orig
• 217:00 - 217:30 valus 100 U value U value 10 m per second s Val 100 U value POS 10 accelerer
• 217:30 - 218:00 always negative G by 9.8 just simple formula s u+ half a t² basic formula s value minus 100 U value 10 t plus half of 9.8 a
• 218:00 - 218:30 value into t² - 4.9 t² + 10 t plus 100.9 10
• 218:30 - 219:00 100 5.65 3611 this will be [Music] answer
• 219:00 - 219:30 5.6 fine simple simple as it is v u + a It Go part V Val + 10 a valus 9.8 T 5.65 9.8 5.65 so this will be our
• 219:30 - 220:00 4.37 m/s velocity will be negative if you follow this process
• 220:00 - 220:30 take
• 220:30 - 221:00 m 30
• 221:00 - 221:30 m f
• 221:30 - 222:00 for
• 222:00 - 222:30 acceleration is acting towards downwards acceler value 9.8 met per second square meter per second
• 222:30 - 223:00 Square
• 223:00 - 223:30 for x h minus X
• 223:30 - 224:00 hus positive 30 m/ second [Music]
• 224:00 - 224:30 S1 equation
• 224:30 - 225:00 S1 U by U1 T1 + half A1 T1 squ s value h x H1 30 30 T1 value T minus
• 225:00 - 225:30 a 9.8 minus 4.9 t² this is our equation number one S2 S2 U2 T2 plus half of A2 T2
• 225:30 - 226:00 s x h this is equal U2 value U2 value Z that 0 minus 4.9 T minus 4 whole Square can T2 Val T minus 4 number equation
• 226:00 - 226:30 okay
• 226:30 - 227:00 for number number equation un h
• 227:00 - 227:30 so right side right [Music] for that's it [Music]
• 227:30 - 228:00 okay [Music]
• 228:00 - 228:30 okay okay
• 228:30 - 229:00 [Music]
• 229:00 - 229:30 a
• 229:30 - 230:00 number [Music]
• 230:00 - 230:30 situation number
• 230:30 - 231:00 for number s Del s by Del y by
• 231:00 - 231:30 this is nothing but the slope of this line
• 231:30 - 232:00 Theta th M1
• 232:00 - 232:30 M2 v v same situ situation third case versus
• 232:30 - 233:00 T
• 233:00 - 233:30 for velocity versus
• 233:30 - 234:00 veloc velocity number number velocity number Point velocity so
• 234:00 - 234:30 L veloc time
• 234:30 - 235:00 change in y by change in X Change in Y versus change in X slocity acceleration
• 235:00 - 235:30 mean V versus T graph V versus T graph a Dalal a minan
• 235:30 - 236:00 a angle Theta 1 a angle Theta 2 a acceleration a2y Delta V by delta T M1 M2 A1
• 236:00 - 236:30 A2 a a applicable for same for s
• 236:30 - 237:00 V so a
• 237:00 - 237:30 analysis A V versus T gra are
• 237:30 - 238:00 HC V versus
• 238:00 - 238:30 positive
• 238:30 - 239:00 Val
• 239:00 - 239:30 negative 10 9 plus something T thet negative T T3
• 239:30 - 240:00 [Music] so
• 240:00 - 240:30 a acceleration a t T1 acceleration T2 same acceleration so
• 240:30 - 241:00 2 m/
• 241:00 - 241:30 square 2 me/ square
• 241:30 - 242:00 sometimes okay fine mainly acceleration versus time velocity versus
• 242:00 - 242:30 time ini
• 242:30 - 243:00 proportional to GT
• 243:00 - 243:30 acceleration value always 9. [Music] 9.8 9.8 acceleration equation me/ second Square H versus T H versus T
• 243:30 - 244:00 same
• 244:00 - 244:30 next problem
• 244:30 - 245:00 vity
• 245:00 - 245:30 v h for
• 245:30 - 246:00 at
• 246:00 - 246:30 n homework homewor secondat problem KitKat
• 246:30 - 247:00 problem problem so sorry com okay
• 247:00 - 247:30 V
• 247:30 - 248:00 V of a
• 248:00 - 248:30 AOC 5 m second V of B 15 V of B 15 M second V2 minus V1 / t v
• 248:30 - 249:00 v that 10us 0 so 10 by 10 that means 1 met per second Square This Is The Answer problem answer
• 249:00 - 249:30 acceleration 1 m
• 249:30 - 250:00 squ s of ab UT plus half a t² u value 5 U value 5 plus oh 10 half of acceleration 1 into 10 square so 5 into 10 +5 into
• 250:00 - 250:30 through
• 250:30 - 251:00 s of BC V
• 251:00 - 251:30 10 10 second
• 251:30 - 252:00 final velocity minus initial velocity
• 252:00 - 252:30 divided by time C final velocity 15 by 8 that means
• 252:30 - 253:00 1.875 s of CD s of CD this is equal UT + half of sare half 1.875
• 253:00 - 253:30 1.875 into 8 S 8 second 15 into 8 +5 into - 1.875 5 into 80 squ so value 60 M
• 253:30 - 254:00 okay this is the answer M alternative approach M fine sorry M alternative V versus T
• 254:00 - 254:30 gra area
• 254:30 - 255:00 okay A B C D E just o a b e a e b c
• 255:00 - 255:30 d a a half
• 255:30 - 256:00 [Music] [Music]
• 256:00 - 256:30 BC BC [Music]
• 256:30 - 257:00 into into x.5 into 28 into similar answer
• 257:00 - 257:30 so BC CD okay
• 257:30 - 258:00 second
• 258:00 - 258:30 okay V 2 minus V1 by
• 258:30 - 259:00 T V minus U divid by T same V2 Val minus Z 5
• 259:00 - 259:30 fine plus
• 259:30 - 260:00 half S Plus half a value 5 into T Val second 60 Square so equation 60 square into 5
• 260:00 - 260:30 2 for
• 260:30 - 261:00 I'm very much sorry V Val 0 4 minus 0 time 20 20us 0
• 261:00 - 261:30 4 1 by 5 squ 1 2 into 0.2 into 60 squ that means
• 261:30 - 262:00 a answer .5 into 2 into 60 square m m sorry
• 262:00 - 262:30 dis V Z [Music]
• 262:30 - 263:00 double
• 263:00 - 263:30 finally
• 263:30 - 264:00 change velocity CH in
• 264:00 - 264:30 timeus final velocity a velocity minus 0us 0 ID 60 minus 0 60 minus 0 0.2 m/
• 264:30 - 265:00 second Square Square final velocity 0 minus initial
• 265:00 - 265:30 velocity divided final time minus minus acceleration Val val3 m/ second square3
• 265:30 - 266:00 M3 squ [Music] okay
• 266:00 - 266:30 problem C graph velocity versus Time same graph
• 266:30 - 267:00 so constant a b o
• 267:00 - 267:30 Okay so
• 267:30 - 268:00 so
• 268:00 - 268:30 one [Music]
• 268:30 - 269:00 supp soose
• 269:00 - 269:30 phys prepar fut thank you